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$CH_2 = CH - (CH_2)_5COOH \xrightarrow[HBr]{\text{Peroxide}} Z$,where $Z$ is:
- A$CH_3 - CH(Br) - (CH_2)_5COOH$
- B$BrCH_2 - (CH_2)_6COOH$
- C$CH_2 = CH - (CH_2)_5 - CH_2OH$
- D$C_6H_5COOH$
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The major product of the following reaction is $:$
The product obtained by the reaction of propene with $HBr$ in the presence of peroxide is......
Medium
View SolutionWhat are the products formed in the reaction given below:
$Ph-CH_2-CH=CH-CH_3 \xrightarrow[Zn \text{ dust } + H_2O]{1) O_3} ?$
$Ph-CH_2-CH=CH-CH_3 \xrightarrow[Zn \text{ dust } + H_2O]{1) O_3} ?$
Identify the major products $X$ and $Y$ in the following reactions:
$(i)$ $C_6H_5-CH=CH_2 + HBr \rightarrow X$
(ii) $C_6H_5-CH_2-CH=CH_2 + HBr \xrightarrow{\text{Peroxide}} Y$
$(i)$ $C_6H_5-CH=CH_2 + HBr \rightarrow X$
(ii) $C_6H_5-CH_2-CH=CH_2 + HBr \xrightarrow{\text{Peroxide}} Y$
Which of the following is obtained by the hydroboration-oxidation of $propene$?
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